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Test: Swift - Optional Binding
5. var name = “San Francisco”; if let name=name {print(name)} else {print(“None”)} - what does this print?
Results Congratulations! Correct Answer. You Answered: None. If you took the test, your answer will show up here. Correct Answer: There will be an error Explanation There will be an error. Because the name here is not of Optional type. The variable name is of type String — not String?. For a Conditional Binding / Optional Binding to occur, the variable/constant bound to must be optional. So, if the name is declared as optional, it would work. var name: String? = “San Francisco” — that will work.Take the Test Take the complete test on this topic. You will be able to review answers to questions and get a test score.
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Question 5 of 5
Test is Based on this Article
This article discusses the safer ways of unwrapping an optional in Swift that includes Optional Binding.
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Test on using Optional Binding in Swift.
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