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Test: Swift - Implicit Unwrapping of Optionals

1. var name: String!; name=“San Francisco!”; print(name) - what does it print?



Results
Congratulations! Correct Answer.
You Answered: None. If you took the test, your answer will show up here.
Correct Answer: San Francisco!
Explanation
Here name is implicitly unwrapped (because of ! next to it). So, when printing it, there is no need to explicitly unwrap it. The name string itself has a ! - “San Francisco!”, so, that will be printed as a string.
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Question 1 of 5


Test is Based on this Article
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This article talks about unwrapping the optionals in Swift implicitly and the circumstances where you would use this functionality.
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Test on how and when optionals are implicitly unwrapped in Swift.

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