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Test: Swift - Forced Unwrapping of Optionals

3. var name: String? = “San “; print(name+”Francisco”) - What does it print?



Results
Congratulations! Correct Answer.
You Answered: None. If you took the test, your answer will show up here.
Correct Answer: Error - doesn’t print anything
Explanation
For the Optional String name to be concatenated with String literal “Francisco”, the name needs to be unwrapped. This is done by using name!. So, using print(name!+”Francisco”) will print San Francisco.
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Question 3 of 5


Test is Based on this Article
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This article talks about getting the value wrapped inside an optional by unwrapping it forcibly.
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Test on Forced Unwrapping of the Optionals in Swift.

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